If the points (2,3),(−5,6) are to be on the opposite side of the line 2x−3y+k=0 then
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a
k > 5
b
k > 28
c
k < 28
d
5 < k < 28
answer is D.
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Detailed Solution
Let A(2,3),B(−5,6) are two points L=2x-3y+k=0 ⇒ L11=4−9+k = k- 5 and L22=−10−18+k =k-28 since A,B are on opposite sides of straight line ⇒L11 , L22 have opposite signs ,so L11·L22<0 ⇒ k-5k-28<0 ⇒ 5