Q.

If the points (2, 0), (0, 1), (4, 5) and (0, c) are concyclic, then the value of 3c, is

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answer is 14.

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Detailed Solution

The equation of the circle passing through (2, 0), (0, 1) and (4, 5) is3x2+y2−13x−17y+14=0This passes through (0, c).∴ 3c2−17c+14=0⇒c=1,14/3Since c = 1 is already there for point (0, 1). Therefore c = 14 / 3.
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