If points i^+j^,i^−j^ and pi^+qj^+rk^ are collinear, then p+r=
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a
1
b
0
c
5
d
4
answer is A.
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Detailed Solution
Points A(i^+j^),B(i^−j^) and C(pi^+qj^+rk^) are collinear Now AB→=−2j^ and BC→=(p−1)i^+(q−1)j^+rk^ Vectors AB→ and BC→ must be collinear ⇒ p=1,r=0 and q≠1