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$If points \hat{i} + \hat{j}, \hat{i} - \hat{j} and p \hat{i} + q \hat{j} + r \hat{k} are collinear, then p+r=$

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Points A(i^+j^),B(i^−j^) and C(pi^+qj^+rk^) are collinear Now AB→=−2j^ and BC→=(p−1)i^+(q−1)j^+rk^ Vectors AB→ and BC→ must be collinear ⇒ p=1,r=0 and q≠1

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If points i^+j^,i^−j^ and pi^+qj^+rk^ are collinear, then p+r=

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$If points \hat{i} + \hat{j}, \hat{i} - \hat{j} and p \hat{i} + q \hat{j} + r \hat{k} are collinear, then p+r=$