If the points (1, 1, p) and (-3, 0, 1) are equidistant from the plane r (3i+4j-12k) +13 =0 then the value of 3p is (3p>4)
Equation of the plane is
3x+4y−12z+13=0|3+4−12p+13|=|−9−12+13|⇒20−12p=8⇒p=1,73