If the points (1, 1, p) and (-3, 0, 1) are equidistant from the plane r (3i+4j-12k) +13 =0 then the value of 3p is (3p>4)

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answer is 7.

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Detailed Solution

Equation of the plane is 3x+4y−12z+13=0|3+4−12p+13|=|−9−12+13|⇒20−12p=8⇒p=1,73

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