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If the points represented by complex numbers z1=a+ib,z2=c+id  and  z1z2  are collinear, where i=1 then 

a
ad+bc=0
b
ad−bc=0
c
ab+cd=0
d
ab−cd=0

detailed solution

Correct option is B

Since,  z1,z2  and  z1−z2  are collinear∴ z1z¯11z2z¯21z1−z2z1−z2¯1=0                ⇒ z1z¯11z2z¯21z1−z2z¯1−z¯21=0Applying R3→R3−R1+R2, then z1z¯11z2z¯21001   =0                                           z1z¯2−z¯1z2    =0⇒                    z1z¯2−z 1z¯2    =0⇒                        Im⁡z1z¯2    =0⇒                          ⇒                            Im⁡((a+ib)(c−id))    =0⇒                             bc−ad=0⇒ad−bc    =0

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