If PQ is the focal chord of parabola y2=−x and P is (−4,2), then the slope of tangent at Q is
2
3
4
5
y2=−x⇒2ydydx=−1∴ Slope of tangent at P,dydx(−4,2)=−14 slope of normal at P =4⇒ Slope of tangent at Q=4 since tangent at one end of focal is parallel to the noral at the other end