If the primitive of f(x)=13sin⁡x+sin3⁡xis equal to 16log⁡t−1t+1+112log⁡2+t2−t+C then

∫dx3sin⁡x+sin3⁡x=∫sin⁡xdx3+sin2⁡xsin2⁡x=∫sin⁡xdx4−cos2⁡x1−cos2⁡x=−∫dt4−t21−t2=−13∫1t2−4−1t2−1 (t=cos⁡x)=16log⁡t−1t+1+112log⁡2+t2−t+C