If the product of the roots of the equation x2−5kx+2e4ln⁡k−1=0 is 31 then sum of the root is

We have product of the roots=2e4ln⁡k−1=31 (given)⇒                                e4ln⁡k=16⇒                                k4=16⇒k4−16=0⇒                                (k−2)(k+2)k2+4=0⇒                                k=2,−2As k > 0, we get k = 2. Sum of the roots = 5k = 10