If the product of the roots of the equation (a+1)x2+(2a+3)x+(3a+4)=0 be 2, then the sum of roots is
1
-1
2
-2
It is given that
αβ=2⇒3a+4a+1=2⇒3a+4=2a+2⇒a=-2
Also α+β=-2a+3a+1
Putting this value of a, we get sum of roots
=-2a+3a+1=--4+3-2+1=-1.