Q.

If the products of roots of the equation x2-3kx+2e2log k-1=0is 7, then its roots will real when

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a

k=1

b

k=2

c

k=3

d

None of these

answer is B.

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Detailed Solution

Given equation can be written asx2-3kx+2k2-1=0So the product of roots is 2k2-1. But the product of roots is 7. Hence 2k2-1=7⇒2k2=8⇒k=±2But k cannot be negative.
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