First slide

Introduction to sets

Question

If $Q = \{x : x = \frac{1}{y}, where y \in N\}$ , then

Easy

A

$0 \in Q$
B

$1 \in Q$
C

$2 \in Q$
D

$\frac{2}{3} \in Q$

Solution

Since $\frac{1}{y} \neq 0, \frac{1}{y} \neq 2, \frac{1}{y} \neq \frac{- 2}{3}, [∴ y \in N]$
$∴ \frac{1}{y} can be 1, [∴ y can be 1] .$

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