If the quadratic equation ax2+bx+c=0(a>0) has sec2 θand cosec2 θas its roots, then which of the following must hold good?
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a
b+c=0
b
b2−4ac≥0
c
c≥4a
d
4a+b≥0
answer is A.
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Detailed Solution
sec2 θ+cosec2 θ=sec2 θ⋅cosec2 θSum of the roots is equal to their product and the roots are real. Hence,−ba=caor b+c=0Also, b2−4ac≥0or c2−4ac≥0or c(c−4a)≥0or c−4a≥0 (∵c>0) Further b2+4ab≥0 or b+4a≤0 (∵b<0)