If the quadrilateral formed by the lines ax+by+c=0 , a′x+b′y+c=0,ax+by+c′=0,a′x+b′y+c′=0 has
perpendicular diagonals, then
b2+c2=b′2+c′2
c2+a2=c′2+a′2
a2+b2=a′2+b′2
None of these
Since the diagonals are perpendicular, the given quadrilateral is a rhombus.
So, the distances between two pairs of parallel sides are equal.
Hence,c′−ca2+b2=∣c′−ca′2+b′2 or a2+b2=a12+b12