If R be a relation < from A=1, 2, 3, 4 to B=1, 3, 5 i.e., a, b∈R⇔a<b, then
RoR-1 is
1, 3,1, 5,2, 3,2, 5,3, 5,4, 5
3, 1,5, 1,3, 2,5, 2,5, 3,5, 4
3, 3,3, 5,5, 3,5, 5
3, 3,3, 4,4, 5,
We have, R=1, 3; 1, 5; 2, 3; 2, 5; 3, 5; 4, 5
R-1=1, 3; 5, 1; 3, 2; 5, 2; 5, 3; 5, 4
Hence RoR-1=3, 3; 3, 5; 5, 3; 5, 5.