If a1,a2 , a3, 5,4, a6 , a7, a8, a9 are in H.P. and the value of the determinant a1a2a354a6a7a8a9 is D, then the value of 21D is
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answer is 50.
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Detailed Solution
We have a1,a2 , a3, 5,4, a6 , a7, a8, a9 are in H.P. we get an=20n d=120 and a1a2a354a6a7a8a9 = D D=2020220320420520620720820 9 ( since 1a1,1a2,1a3 ,15,14,....,1a9 are in AP ⇒ common difference =14-15=120 and 4th term = 15=1a1+320⇒a1=20= (20)34x7 1 12 131 45 231 78 79 Applying R1→R1-R2 , R2→R2-R3 , =(20)34x7 0 -310 -130 -340 -191 78 79 =5021 ⇒21D=50