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If $A_{r} = (\begin{array}{cc} r & r - 1 \\ r - 1 & r \end{array})$ where r is a natural number then $\sqrt{[|A_{1}| + |A_{2}| + |A_{3}| + \dots . . . . . . . . + |A_{2008}|]}$ must be equal to

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2008

(2006)2

(2006)3

2007

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detailed solution

Correct option is A

Ar=r2−(r−1)2=2r−1∑r=12008Ar=(2008)2

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If Ar=rr−1r−1r where r is a natural number then A1+A2+A3+…........+A2008 must be equal to

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If $A_{r} = (\begin{array}{cc} r & r - 1 \\ r - 1 & r \end{array})$ where r is a natural number then $\sqrt{[|A_{1}| + |A_{2}| + |A_{3}| + \dots . . . . . . . . + |A_{2008}|]}$ must be equal to