if r→ and s→ are non-zero constant vectors and the scalar D is chosen such that |r→+bs→| is minimum, then the value of |bs→|2+|r→+bs→|2=

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2|r→|2

|r→|22

|r→|2

3|r→|2

answer is C.

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Detailed Solution

For minimum value |r→+bs→|=0let r→ and s→ are anti-parallel so bs→=−r→∴ |bs→|2+|r→+bs→|2=|−r→|2+|r→−r→|2=|r→|2

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