If θ∈R, then maximum value of Δ=11111+sin⁡θ1111+cos⁡θ is

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3/2

1/2

None of these

answer is B.

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Detailed Solution

Applying C2→C2−C1 and C3→C3−C1, we getΔ=1001sin⁡θ010cos⁡θ=sin⁡θcos⁡θ=(sin⁡2θ)/2So, maximum value of Δ is 1/2.

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