If θ∈R, then maximum value of Δ=11111+sinθ1111+cosθ is
3/2
1/2
None of these
Applying C2→C2−C1 and C3→C3−C1, we get
Δ=1001sinθ010cosθ=sinθcosθ=(sin2θ)/2
So, maximum value of Δ is 1/2.