Q.
If θ∈R, then maximum value of Δ=11111+sinθ1111+cosθ is
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a
3/2
b
1/2
c
1/2
d
None of these
answer is B.
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Detailed Solution
Applying C2→C2−C1 and C3→C3−C1, we getΔ=1001sinθ010cosθ=sinθcosθ=(sin2θ)/2So, maximum value of Δ is 1/2.
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