Q.

If r¯ is a vector of magnitude 210 and has direction ratios 2,−3,6, then r¯ =

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a

60i¯−90j¯+180k¯

b

120i¯−180j¯−360k¯

c

12i¯+18j¯−36k¯

d

712i¯+18j¯+36k¯

answer is A.

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Detailed Solution

The vector along another vector a¯with magnitude kunits is ka¯a¯Hence, the vector  r¯ with magnitude 210 units along the vector 2i−3j+6k  is 2102i−3j+6k4+9+36Therefore,  r¯=60i−90j+180k
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