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If $\bar{r}$ is a vector of magnitude 210 and has direction ratios $2, - 3, 6$ , then $\bar{r}$ =

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60i¯−90j¯+180k¯

120i¯−180j¯−360k¯

12i¯+18j¯−36k¯

712i¯+18j¯+36k¯

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detailed solution

Correct option is A

The vector along another vector a¯with magnitude kunits is ka¯a¯Hence, the vector r¯ with magnitude 210 units along the vector 2i−3j+6k is 2102i−3j+6k4+9+36Therefore, r¯=60i−90j+180k

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If r¯ is a vector of magnitude 210 and has direction ratios 2,−3,6, then r¯ =

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Ready to Test Your Skills?

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If $\bar{r}$ is a vector of magnitude 210 and has direction ratios $2, - 3, 6$ , then $\bar{r}$ =