If r¯ is a vector of magnitude 210 and has direction ratios 2,−3,6, then r¯ =
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a
60i¯−90j¯+180k¯
b
120i¯−180j¯−360k¯
c
12i¯+18j¯−36k¯
d
712i¯+18j¯+36k¯
answer is A.
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Detailed Solution
The vector along another vector a¯with magnitude kunits is ka¯a¯Hence, the vector r¯ with magnitude 210 units along the vector 2i−3j+6k is 2102i−3j+6k4+9+36Therefore, r¯=60i−90j+180k