If R=x,y|x, y∈z, x2+y2≤4 is a relation in Z, then domain of R is
0, 1, 2
0, -1, -2
-2, -1, 0, 1, 2
None of these
∵R=x,y|x,y∈Z, x2+y2≤4
∴R={-2, 0, -1, 0, -1, 1, 0, -1, 0, 1, 0, 2, 0, -2, 1, 0, 1, 1, 2, 0}
Hence, Domain of R=-2, -1, 0, 1, 2.