First slide
Introduction to Relations (XI) on Sets
Question

If R=x,y|x, yz, x2+y24 is a relation in Z, then domain of R is

Easy
Solution

R=x,y|x,yZ, x2+y24

R={-2, 0, -1, 0, -1, 1, 0, -1, 0, 1, 0, 2, 0, -2, 1, 0, 1, 1, 2, 0}

Hence, Domain of R=-2, -1, 0, 1, 2.

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