First slide

Introduction to Relations (XI) on Sets

Question

If R= {(x, y): x, y $\in$ Z, x² + y² $\leq$ 4} is relation in Z, then domain of R is

Easy

A
{0,1,2}
B

2. {-2,_1,0}
C

3. {-2,-1,0,1,2}
D

4. None of these

Solution

(3) We have,
R= {(x, y) : x, y $\in$ z, x²+y² $\leq$ }
R= {(0,0), (0,-1),(0,1),(0,-2),(0,2),(-1,0),
Domain of R = { x: (x, y) $\in$ R} = {0,-1, 1,-2,2}

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