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Q.

If the radius of a sphere is increasing at the rate of 0.1 units/sec, then the rate of change in surface area of the sphere  when radius is 10 units is

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a

8π  sq. unit/sec

b

3.2π  sq. unit/sec

c

0.32π  sq. unit/sec

d

32π  sq. unit/sec

answer is A.

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Detailed Solution

drdt=0.1,  r=10 s=4πr2 dsdt=4π.2r.drdt =8π×10×0.1 =8π
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