If the radius of a sphere is increasing at the rate of 0.1 units/sec, then the rate of change in surface area of the sphere when radius is 10 units is

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8π sq. unit/sec

3.2π sq. unit/sec

0.32π sq. unit/sec

32π sq. unit/sec

answer is A.

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Detailed Solution

drdt=0.1, r=10 s=4πr2 dsdt=4π.2r.drdt =8π×10×0.1 =8π

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