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If the ratio of the sum to n terms of two A.P.’s is  5n+3:3n+4 then the ratio of their 17th terms is

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a
17299
b
168103
c
17599
d
171103

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detailed solution

Correct option is B

Given n22a1+(n−1)d1n22a2+(n−1)d2=5n+33n+4a1+n−12d1a2+n−12d2=5n+33n+4=168103  where  n−12=16 n=33


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If the sum of first n terms of an AP is cn2, then the sum of squares of these  n terms is 


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