If the ratio of sums to n terms of two A.P.’s is (5n+7) : (3n+2), then the ratio of their 17th terms is

Let two A.P.'s be      a,a+d,a+2d,a+3d,…and A,A+D,A+2D,A+3D,…According to the given condition, n2[2a+(n−1)d]n2[2A+(n−1)D]=5n+73n+2  ⇒ a+n−12dA+n−12D=5n+73n+2Putting n-12=16 or n=33, we get       a+16dA+16D=5(33)+73(33)+2=172101