Questions
If the ratio of the 7th term from the beginning to the 7th term from the end in the expansion of is then the value of is
detailed solution
Correct option is A
Let a=7th term from the beginning=T7=T6+1=nC621/3n−63−1/36and let b=7th term from the end=(n+2−7) th or (n−5) th term from the beginning=nCn−621/3n−(n−6)3−1/3n−6=nC621/363−1/3n−6we are given ab=1621/3n−63−1/3621/363−1/3n−6=16⇒21/33−1/3n−12=16⇒6(n−12)/3=6−1⇒n−12=−3⇒n=9.Talk to our academic expert!
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The coefficient of x4 in the expansion of is
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