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If $a$ is a real number and if the middle term of ${(\frac{a}{3} + 3)}^{8}$ is 1120, then value of $a$ is

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Correct option is A

Middle term of a3+38 is the 82+1 th or 5th term. We haveT5=T4+1=8C4a34(3)4=70a4We are given T5=1120⇒70a4=1120⇒ a4=16=24⇒a=±2

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If a is a real number and if the middle term of a3+38 is 1120, then value of a is

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If $a$ is a real number and if the middle term of ${(\frac{a}{3} + 3)}^{8}$ is 1120, then value of $a$ is