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Questions  

If a is real and the 4th term in the expansion of ax+1xnis 5/2, for each xR-{0}, then values of n and a are respectively

a
5, 1/2
b
6, -1/2
c
3, 1/3
d
6, 1/2

detailed solution

Correct option is D

We have T4=T3+1=nC3(ax)n−31x3=nC3an−3xn−6=5/2As this is true for each x∈R-{0}, we get         n-6=0 and  nC3an−3=5/2⇒     n=6 and  6C3a3=5/2∴ a3=52×3!3!6!=52×120=18⇒ a=1/2.Thus,      n=6,  a=1/2.

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