If the resultant of three forces F→1=pi^+3j^−k^,F→2=−5i^+j^+2k^ and F→3=6i^−k^ acting on a particle has a magnitude equal to 5 units, then what is difference in the values of p?

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answer is 6.

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Detailed Solution

Let R→ be the resultant. ThenR→=F→1+F→2+F→3=(p+1)i^+4j^ Given, |R→|=5, therefore R2=25∵ (p+1)2+16=25 or p+1=±3 or p=2,−4

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