If in a right-angled triangle ABC, the hypotenuse A B= p, the AB→⋅AC→+BC→⋅BA→+CA→⋅CB→=
2P2
P22
P2
none of these
We haveAB→⋅AC→+BC→⋅BA→+CA→⋅CB→=(AB)(AC)cosθ+(BC)(BA)sinθ+0=AB(ACcosθ+BCsinθ)=AB(AC)2AB+(BC)2AB=AC2+BC2=AB2=p2