Q.

If a root of the equation x2+px+12=0 is 4, while the roots of the equation x2+px+q=0 are same, then the value of q will be

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a

4

b

4/49

c

49/4

d

None of these

answer is C.

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Detailed Solution

Put x=4 in x2+px+12=0, we get p=-7Now second equation x2+px+q=0 have equal roots. Therefore p2=4q⇒q=494
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