Q.
If a root of the given equation a(b-c)x2+b(c-a)x+c(a-b)=0 is 1, then the other will be
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a
a(b-c)b(c-a)
b
b(c-a)a(b-c)
c
c(a-b)a(b-c)
d
None of these
answer is C.
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Detailed Solution
Let α=1 and the other root is β, then product of roots 1.β=c(a-b)a(b-c)⇒β=c(a-b)a(b-c)
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