If the roots of the cubic, x3 + ax2 + bx + c = 0 are three consecutive positive integers, then the value of a2/(b + 1) is equal to _________.

n, n+1, n+2Sum = 3(n + 1) = - a∴ a2=9(n+1)2Sum of the roots taken two at a time = +b∴n(n+1)+(n+1)(n+2)+(n+2)n=bn2+n+n2+3n+2+n2+2n+1=b+1∴b+1=3n2+6n+3b+1=3(n+1)2=a23; ∴a2b+1=3