If the roots of the equation ax2−bx+c=0 are α,β, the roots of the equation b2cx2−ab2x+a3=0 are
1α3+αβ,1β3+αβ
1α2+αβ,1β2+αβ
1α4+αβ,1β4+αβ
none of these
Multiplying the given equation by c/a3, we get
b2c2a3x2−b2ca2x+c=0
or abca2x2−bbca2x+c=0⇒ bca2x=α,β⇒ (α+β)αβx=α,β⇒ x=1(α+β)α,1(α+β)β