If the roots of the equation ax2+bx+c=0 be α and β, then the roots of the equation cx2+bx+a=0 are
-α, -β
α, 1β
1α, 1β
None of these
α, β are roots of ax2+bx+c=0
Let the roots of cx2+bx+a=0 be α', β', then α'+β'=-bc and α'β'=ac
but α+βαβ=-b/ac/a=-bc⇒1α+1β=α1+β1
Hence α'=1α and β'=1β