If the roots of the equation (p2+q2)x2-2q(p+r)x+(q2+r2)=0 be real and equal, then p, q, r will be in

Given equation is 4q2(p+r)2-4(p2+q2)(q2+r2)=0Roots are real and equal, then4q2(p+r)2-4(p2+q2)(q2+r2)=0 ⇒q2(p2+r2+2pr)-(p2q2+p2r2+q4+q2r2)=0 ⇒q2p2+q2r2+2pq2r-p2q2-p2r2-q4-q2r2=0 ⇒2pq2r-p2r2-q4=0⇒(q2-pr)2=0  Hence q2=pr. Thus p, q, r in G.P.