If the roots of the equation qx2+px+q=0 where p, q are real, be complex, then the roots of the equation x2-4qx+p2=0 are

The given equations areqx2+px+q=0    ...(i)and x2-4qx+p2=0    ...(ii)Roots of (i) are complex, therefore p2-4q2<0Now discriminant of (ii) is16q2-4p2=-4(p2-4q2)>0Hence, roots are real and unequal.