If the roots of the equation ax2+bx+c=0 are real and distinct, then

The roots of the given equation areα=−b−b2−4ac2a and β=−b+b2−4ac2aSince α,β are real and distinct, therefore b2−4ac>0It is evident from Fig 1 that β1<−b2a<αSo, one root is less than -b2aand other exceeds -b2a