If the roots of the equation x2−2cx+ab=0 are real  and unequal, the roots of the equation x2−2(a+b)x+a2+b2+2c2=0 are

Since x2−2cx+ab=0 has real and unequal roots, we have c2−ab>0 (∵D>0) For x2−2(a+b)x+a2+b2+2c2=0 Discriminant, D=4(a+b)2−a2+b2+2c2 =42ab−2c2<0Hence, it has imaginary roots.