If the roots of the equation x2−2cx+ab=0 are real and unequal, the roots of the equation x2−2(a+b)x+a2+b2+2c2=0 are

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real and distinct

real and equal

real

imaginary

answer is D.

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Detailed Solution

c2−ab>0 For x2−2(a+b)x+a2+b2+2c2=0 Discriminant, D=4(a+b)2−a2+b2+2c2 =42ab−2c2<0Hence, it has imaginary roots

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