First slide
Cartesian plane
Question

If the roots of the equation

x12a2m22x1y1m+y12+b2=0a>b

are the slopes of two perpendicular lines intersecting at Px1,y1, then the locus of P is 

Moderate
Solution

Equation x12a2m22x1y1m+y12+b2=0 has roots m1 and m2

      m1m2=y12+b2x12a2=1

      x2+y2=a2b2

This is the required locus.

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