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Q.

If roots of the equation x2−2mx+m2−1=0 lie in the interval (– 2, 4), then

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a

– 1 < m < 3

b

1 < m < 5

c

1 < m < 3

d

– 1 < m < 5

answer is A.

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Detailed Solution

x2−2mx+m2−1=0⇒(x−m)2=1⇒x−m=±1⇒x=m±1Therefore, – 2

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If roots of the equation x2−2mx+m2−1=0 lie in the interval (– 2, 4), then