If roots of the equation x2−2mx+m2−1=0 lie in the interval (– 2, 4), then
– 1 < m < 3
1 < m < 5
1 < m < 3
– 1 < m < 5
x2−2mx+m2−1=0⇒(x−m)2=1
⇒x−m=±1⇒x=m±1
Therefore, – 2<m–1<m+1<4
⇒−1<m<3