If roots of an equation xn−1=0 are 1,a1,a2,…,an−1, then the value of 1−a11−a21−a3⋯1−an−1 will be
n
n2
nn
0
Clearly,
xn−1=(x−1)x−a1x−a2⋯x−an−1⇒xn−1x−1=x−a1x−a2⋯x−an−1⇒1+x+x2+⋯+xn−1=x−a1x−a2⋯x−an−1⇒n=1−a11−a2⋯1−an−1 [putting x=1