If roots of an equation xn−1=0 are 1,a1,a2,…,an−1, then the value of 1−a11−a21−a3............(1-an-1) will be
n
n2
nn
None of these
Clearly,xn−1=(x−1)x−a1x−a2…x−an−1
⇒ xn−1x−1=x−a1x−a2…x−anLHS is the summation of series in GP⇒ 1+x+x2+…+xn−1=x−a1x−a2…x−an−1
⇒n=1−a11−a2…1−an−1 [putting x=1]