If the roots of equation x2+px+q=0 differ by 1, then
p2=4q
p2=4q+1
p2=4q-1
None of these
Let the roots of the equation be α, β
Given α-β=1
∴ (α-β)2=(α+β)2-4αβ⇒(1)2=(-p)2-4q
∴p2=4q+1