If the roots of the equation 8x3−14x2+7x−1=0are in GP, then the roots are

Since, the roots of the equation 8x3−14x2+7x−1=0are in GP. Let the roots αβ,α,αβ,β≠0. Then, the product of roots is α3=18⇒α=12 and hence, β=12So, roots are 1,12,14