If the roots of the quadratic equation (4p−p2−5)x2−(2p−1)x+3p=0  lie on either side of unity, the number of integral values of p is

Since, the coefficient of  x2=(4p−p2−5)<0Therefore, the graph is open downward. According to the question, 1 must lie between the roots. Hence,⇒f(1)>0⇒4p−p2−5−2p+1+3p>0⇒−p2+5p−4>0⇒p2−5p+4<0⇒(p−4)(p−1)<0⇒1