If roots of the quadratic equation ax2+bx+c=0 are real and are of the form αα−1,α+1α, then value of (a+b+c)2 is

αα−1+α+1α=−ba, and αα−1⋅α+1α=caNow, (a+b+c)2=a21+ba+ca2=a21−αα−1+α+1α+α+1α−12=a2αα−1−α+1α2=a2αα−1+α+1α2−4αα−1⋅α+1α=a2b2a2−4ca=b2−4ac