If the roots of ax2+bx+c=0(a>0) be each greater than unity, then
a+b+c=0
a+b+c>0
a+b+c<0
none of these
Let f(x)=ax2+bx+c. Since 1 lies outside the roots of f (x) = 0. So, af(1)>0⇒ f(1)>0⇒a+b+c>0 [∵a>0]