First slide

Trigonometric equations

Question

If $S i n (\frac{π C o t θ}{4}) = C o s (\frac{π T a n θ}{4})$ and $θ$ is in the first quadrant then $θ$ =-----

Moderate

A

$\frac{π}{3}$
B

$\frac{π}{2}$
C

$\frac{π}{4}$
D

$\frac{π}{6}$

Solution

$\sin (\frac{π \cot θ}{4}) = \cos (\frac{π \tan θ}{4})$
on verification $θ = \frac{π}{4}$ satisfies

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