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If $S i n^{- 1} x - C o s^{- 1} x = \frac{π}{6}$ then x=

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Correct option is A

Given sin-1x-cos-1x=π6 ⇒sin-1x-π2-sin-1x=π6 ⇒sin-1x=π3 ⇒x=sinπ3=32

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If Sin−1x−Cos−1x=π6then x=

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If $S i n^{- 1} x - C o s^{- 1} x = \frac{π}{6}$ then x=